b^2-10b+27=2

Solution for b^2-10b+27=2 equation:

Simplifying
b2 + -10b + 27 = 2

Reorder the terms:
27 + -10b + b2 = 2

Solving
27 + -10b + b2 = 2

Solving for variable 'b'.

Reorder the terms:
27 + -2 + -10b + b2 = 2 + -2

Combine like terms: 27 + -2 = 25
25 + -10b + b2 = 2 + -2

Combine like terms: 2 + -2 = 0
25 + -10b + b2 = 0

Factor a trinomial.
(5 + -1b)(5 + -1b) = 0

Subproblem 1
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {5, 5}